Re: darmowe ciepło w zimie - Grupy dyskusyjne w eGospodarka.pl

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Subject: Re: darmowe ciepło w zimie
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W kilowatach bedzie to tak. P=1000kg(1000m3) x 1kJ/(kg x K) x 10°K x 4,19J : 3600
sek. Daje to cirka jebalt 11,5 kW. 1000m? powietrza przy studzeniu o 10 stopni odda
11,5 kW.